Chemistry: Problems/ solutions in Boyle's Law - Answer

Boyle's Law Problems
1.  The volume of the lungs is measured by the volume of air inhaled or exhaled.  If the 
     volume of the lungs is 2.400 L during exhalation and the pressure is 101.70 KPa, and the
     pressure during inhalation is 101.01 KPa, what is the volume of the lungs during inhalation? 
    V₂ = [V₁][P₁]          V₂ = [2.400L][101.70KPa]  =  2.412L
                   [P₂]                                 [101.01KPa]
2.  The total volume of a soda can is 415 mL.  Of this 415 mL, there is 60.0 mL of headspace
     for the CO₂ gas put in to carbonate the beverage.  If a volume of 100.0 mL of gas at
     standard pressure is added to the can, what is the pressure in the can when it has been
      sealed?
    P₂ = [V₁][P₁]          P₂ = [100.0 mL][101.3KPa]  =  169 KPa
            [V₂]                         [60.0 mL]
3.  It is hard to begin inflating a balloon.  A pressure of 800.0 Kpa is required to initially inflate
     the balloon 225.0 mL.  What is the final pressure when the balloon has reached it's capacity
     of 1.2 L?
     P₂ = [V₁][P₁]          P₂ = [0.225L][800.0 KPa]  =  150 KPa
             [V₂]                         [1.2 L]
4.  If a piston compresses the air in the cylinder to 1/8 it's total volume and the volume is
     930 cm³  at STP, what is the pressure after the gas is compressed? 
      P₂ = [V₁][P₁]          V₂ = [930cm³ ][101.3 KPa]  =  810 KPa
              [V₂]                         [930/8cm³]
5.  If a scuba tank that has a capacity of 10.0 dm³  is filled with air to 500.0 KPa, what will be
     the volume of the air at 702.6 KPa? 
     V₂ = [V₁][P₁]          V₂ = [10.0 dm³][500.0KPa]  =  7.11 dm³
                    [P₂]                                    [702.6KPa]